A spherical surface of radius 3 mm is centered at P 4, 1, 5 in free space. The outer conductor thickness is 0. Hayt, Jr. Buck — Details — Trove Trying this with the given materials yields the winner, which is barium titanate. The problem did not provide information necessary to determine this.
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Solution Manual Engineering Electromagnetics Hayt Buck
Engineering Electromagnetics by William Hayt & John Buck